Bring all terms: ( \sin x \cos x - \frac12\sin x = 0 ) ( \sin x (\cos x - 1/2) = 0 )
( 2\sin x = 1 ) ( \cos^2 x - \sin^2 x = 0 ) ( \tan(2x) = \sqrt3 )
Let ( t = 2x ). Solve ( \tan t = 1 ). Principal value: ( t = \pi/4 ). Tangent period is ( \pi ): ( t = \pi/4 + k\pi ). Thus ( 2x = \pi/4 + k\pi \Rightarrow x = \pi/8 + k\pi/2 ).
( 0,\ \pi/3,\ \pi,\ 5\pi/3 ). Type 4: Equation with tangent Example: ( \tan(2x) = 1 ) in ( [0, 2\pi) ).
( \pi/8,\ 5\pi/8,\ 9\pi/8,\ 13\pi/8 ). Type 5: Equation with sine and cosine of the same angle Example: ( \sin x = \cos x ).
Find ( k ) for ( 0 \le x < 2\pi ): ( k=0 \to \pi/8 ) ( k=1 \to \pi/8 + \pi/2 = 5\pi/8 ) ( k=2 \to 9\pi/8 ) ( k=3 \to 13\pi/8 ) ( k=4 \to 17\pi/8 = 2\pi + \pi/8 ) (too large).
Ecuaciones Trigonometricas 1 Bachillerato !!link!! May 2026
Bring all terms: ( \sin x \cos x - \frac12\sin x = 0 ) ( \sin x (\cos x - 1/2) = 0 )
( 2\sin x = 1 ) ( \cos^2 x - \sin^2 x = 0 ) ( \tan(2x) = \sqrt3 )
Let ( t = 2x ). Solve ( \tan t = 1 ). Principal value: ( t = \pi/4 ). Tangent period is ( \pi ): ( t = \pi/4 + k\pi ). Thus ( 2x = \pi/4 + k\pi \Rightarrow x = \pi/8 + k\pi/2 ).
( 0,\ \pi/3,\ \pi,\ 5\pi/3 ). Type 4: Equation with tangent Example: ( \tan(2x) = 1 ) in ( [0, 2\pi) ).
( \pi/8,\ 5\pi/8,\ 9\pi/8,\ 13\pi/8 ). Type 5: Equation with sine and cosine of the same angle Example: ( \sin x = \cos x ).
Find ( k ) for ( 0 \le x < 2\pi ): ( k=0 \to \pi/8 ) ( k=1 \to \pi/8 + \pi/2 = 5\pi/8 ) ( k=2 \to 9\pi/8 ) ( k=3 \to 13\pi/8 ) ( k=4 \to 17\pi/8 = 2\pi + \pi/8 ) (too large).